x^2+(-0,67x-3,67)=25

Solution for x^2+(-0,67x-3,67)=25 equation:

x^2+(-0.67x-3.67)=25

We move all terms to the left:

x^2+(-0.67x-3.67)-(25)=0

We get rid of parentheses

x^2-0.67x-3.67-25=0

We add all the numbers together, and all the variables

x^2-0.67x-28.67=0

a = 1; b = -0.67; c = -28.67;
Δ = b2-4ac
Δ = -0.672-4·1·(-28.67)
Δ = 115.1289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.67)-\sqrt{115.1289}}{2*1}=\frac{0.67-\sqrt{115.1289}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.67)+\sqrt{115.1289}}{2*1}=\frac{0.67+\sqrt{115.1289}}{2}
$